Atoms And Nuclei Question 29
Question: Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength $ \lambda $ of that electron as [CBSE PMT 1990]
Options:
A) $ (0.259)\ n\lambda $
B) $ \sqrt{n}\lambda $
C) $ (13.6)\ \lambda $
D) $ n\lambda $
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Answer:
Correct Answer: D
Solution:
According to Bohr’s theory $ mvr=n\frac{h}{2\pi } $
Þ Circumference $ 2\pi r=n,( \frac{h}{mv} )=n\lambda $
BETA
