Atoms And Nuclei Question 294
Question: Which of the following transitions in hydrogen atoms emit photons of highest frequency?
Options:
A) n=1 to n=2
B) n=2 to n=6
C) n=6 to n=2
D) n=2 to n=1
Show Answer
Answer:
Correct Answer: D
Solution:
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Frequency is given by $ hv=13.6( \frac{1}{n _{1}^{2}}-\frac{1}{n _{2}^{2}} ) $
For transition from n=6 to n=2, $ v _{1}=\frac{-13.6}{h}( \frac{1}{6^{2}}-\frac{1}{2^{2}} )=\frac{2}{9}\times ( \frac{13.6}{h} ) $
For transition from n=2 to n=1, $ v _{2}=\frac{-13.6}{h}( \frac{1}{2^{2}}-\frac{1}{1^{2}} )=\frac{3}{4}\times ( \frac{13.6}{h} ). $
$ \therefore v _{1}>v _{2} $
BETA
