Atoms And Nuclei Question 3
Question: In the nth orbit, the energy of an electron $ E_{n}=-\frac{13.6}{n^{2}}eV $ for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be [MP PMT 1987; CPMT 1991, 97; RPMT 1999; DCE 2001; Kerala PMT 2004]
Options:
A) $ 10.2\ eV $
B) $ 12.1\ eV $
C) $ 13.6\ eV $
D) $ 3.4\ eV $
Show Answer
Answer:
Correct Answer: A
Solution:
$ {E_{1\to 2}}=-3.4-(13.6)=+10.2,eV $
BETA
