Atoms And Nuclei Question 330
Question: If the nuclear radius of $ ^{27}Al $ is 3.6 Fermi, the approximate nuclear radius of $ ^{64}Cu $ in Fermi is
Options:
A) 4.8
B) 3.6
C) 2.4
D) 1.2
Show Answer
Answer:
Correct Answer: A
Solution:
- Nuclear radius, $ r\propto {{A}^{1/3}} $ where A is mass number $ \frac{r_{Cu}}{r_{Al}}={{( \frac{A_{Cu}}{A_{Al}} )}^{1/3}}={{( \frac{64}{27} )}^{1/3}} $
$ \Rightarrow r_{Cu}=3.6( \frac{4}{3} )=4.8,Fermi $
BETA
