Communication System Question 12
Question: A TV tower has a height of 100 m. How much population is covered by the TV broadcast if the average population density around the tower is $ 1000,k{{m}^{-2}} $ ? (Radius of the earth $ =6.37\times 10^{6}m $ )
Options:
A) 4 lakh
B) 4 billion
C) 40,000
D) 40 lakh
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ d=\sqrt{2hR} $ Population covered
$ =\pi d^{2}\times Population,density $
$ =\pi \times 2hR\times Population,density $
$ =\frac{3.14\times 2\times 100\times 6.37\times 10^{6}\times 1000}{1000\times 1000} $
$ =4\times 10^{6} $
BETA
