Current Electricity Charging Discharging Of Capacitors Question 270
Question: AB is a potentiometer wire of length 100 cm and its resistance is 10 ohms. It is connected in series with a resistance R = 40 ohms and a battery of e.m.f. 2 V and negligible internal resistance. If a source of unknown e.m.f. E is balanced by 40 cm length of the potentiometer wire, the value of E is
[MP PET 2001]
Options:
A) 0.8 V
B) 1.6 V
C) 0.08 V
D) 0.16 V
Show Answer
Answer:
Correct Answer: D
Solution:
$ E=\frac{e}{(R+R _{h}+r)},\frac{R}{L}\times l $
$ =\frac{2}{(10+40+0)}\times \frac{10}{1}\times 0.4=0.16V $ .
BETA
