Current Electricity Charging Discharging Of Capacitors Question 272
Question: In a circuit 5 percent of total current passes through a galvanometer. If resistance of the galvanometer is G then value of the shunt is
[MP PET 2001]
Options:
A) 19 G
B) 20 G
C) $ \frac{G}{20} $
D) $ \frac{G}{19} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{i _{g}}{i}=\frac{S}{G+S} $
Therefore $ \frac{5}{100}=\frac{S}{G+S} $
Therefore $ S=\frac{G}{19} $
BETA
