Current Electricity Charging Discharging Of Capacitors Question 274
Question: In a potentiometer experiment two cells of e.m.f. E1 and E2 are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the polarity of E2 is reversed, then the balancing length becomes 29 cm. The ratio $ \frac{E _{1}}{E _{2}} $ of the e.m.f. of the two cells is
[Kerala (Engg.) 2001]
Options:
A) 1 : 1
B) 2 : 1
C) 3 : 1
D) 4 : 1
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{E _{1}}{E _{2}}=\frac{l _{1}+l _{2}}{l _{1}-l _{2}}=\frac{58+29}{58-29}=\frac{3}{1} $
BETA
