Current Electricity Charging Discharging Of Capacitors Question 116
Question: If 1 A of current is passed through $ CuSO _{4} $ solution for 10 seconds, then the number of copper ions deposited at the cathode will be about
Options:
A) $ 1.6\times 10^{19} $
B) $ 3.1\times 10^{19} $
C) $ 4.8\times 10^{19} $
D) $ 6.2\times 10^{19} $
Show Answer
Answer:
Correct Answer: B
Solution:
Total charge supplied $ =1\times 10=10,C $
$ \because $ 2 electronic charge $ (3.2\times {{10}^{-19}}C) $ liberates one $ C{{u}^{++}} $ ion \ Number of $ C{{u}^{++}} $ ions liberated by 10 C charge $ =\frac{1}{3.2\times {{10}^{-19}}}\times 10 $
$ =3.1\times 10^{19} $
BETA
