Current Electricity Charging Discharging Of Capacitors Question 117
Question: A silver and a copper voltmeters are connected in parallel across a 6 volt battery of negligible resistance. In half an hour, 1 gm of copper and 2 gm of silver are deposited. The rate at which energy is supplied by the battery will approximately be (Given E.C.E. of copper $ =3.294\times {{10}^{-4}},g/C $ and E.C.E. of silver $ =1.118\times {{10}^{-3}},g/C) $
Options:
A) 64 W
B) 32 W
C) 96 W
D) 16 W
Show Answer
Answer:
Correct Answer: D
Solution:
$ \because $
$ m=Zit $ or $ i=\frac{m}{Zt} $ For silver voltmeter $ i _{1}=\frac{m _{1}}{Z _{1}t}=\frac{2}{1.118\times {{10}^{-3}}\times 1800}=0.994amp $ For copper voltameter $ i _{2}=\frac{m _{2}}{Z _{2}t}=\frac{1}{3.294\times {{10}^{-4}}\times 1800}=1.687amp $ \ Power of circuit $ =V(i _{1}+i _{2}) $
$ =6\times (0.994+1.687) $
$ =6\times 2.681\approx 16W $
BETA
