Current Electricity Charging Discharging Of Capacitors Question 291
Question: An ammeter of 100 W resistance gives full deflection for the current of 10?5 amp. Now the shunt resistance required to convert it into ammeter of 1 amp. range, will be
[RPET 2003]
Options:
A) $ {{10}^{-4}} $ W
B) $ {{10}^{-5}} $ W
C) $ {{10}^{-3}} $ W
D) $ {{10}^{-1}} $ W
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{i}{i _{g}}=1+\frac{G}{S}\Rightarrow \frac{1}{{{10}^{-5}}}=1+\frac{100}{S} $
$ \Rightarrow S\approx \frac{100}{10^{5}}={{10}^{-3}}\Omega $ .
BETA
