Current Electricity Charging Discharging Of Capacitors Question 292
Question: A galvanometer of resistance 36 W is changed into an ammeter by using a shunt of 4 W. The fraction f0 of total current passing through the galvanometer is
[BCECE 2003]
Options:
A) $ \frac{1}{40} $
B) $ \frac{1}{4} $
C) $ \frac{1}{140} $
D) $ \frac{1}{10} $
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Answer:
Correct Answer: D
Solution:
$ \frac{i _{g}}{i}=\frac{S}{G+S}=\frac{4}{36+4}=\frac{4}{40}=\frac{1}{10} $
BETA
