Current Electricity Charging Discharging Of Capacitors Question 198
Question: An ammeter of 5 ohm resistance can read 5 mA. If it is to be used to read 100 volts, how much resistance is to be connected in series
[MP PET 1991; MP PMT 1996; MP PMT 2000]
Options:
A) $ 19.9995,\Omega $
B) $ 199.995\Omega $
C) $ 1999.95,\Omega $
D) $ 19995,\Omega $
Show Answer
Answer:
Correct Answer: C
Solution:
By using $ R=\frac{V}{I _{g}}-G $
Therefore $ R=\frac{100}{5\times {{10}^{-3}}}-5=19,995\Omega $
BETA
