Current Electricity Charging Discharging Of Capacitors Question 303
Question: What is the reading of voltmeter in the following figure
[MP PMT 2004]
Options:
A) 3 V
B) 2 V
C) 5 V
D) 4 V
Show Answer
Answer:
Correct Answer: D
Solution:
Resistance between A and B $ =\frac{1000\times 500}{(1500)}=\frac{1000}{3} $ So, equivalent resistance of the circuit $ R _{eq} $
$ =500+\frac{1000}{3}=\frac{2500}{3} $ \ Current drawn from the cell $ i=\frac{10}{(2500/3)} $
$ $
$ =\frac{3}{250}A $ Reading of voltmeter i.e. potential difference across $ AB=\frac{3}{250}\times \frac{1000}{3}=4,V $
BETA
