Current Electricity Charging Discharging Of Capacitors Question 304
Question: The current flowing in a coil of resistance 90 W is to be reduced by 90%. What value of resistance should be connected in parallel with it
[MP PMT 2004]
Options:
9 W
B) 90 W
C) 1000 W
D) 10 W
Show Answer
Answer:
Correct Answer: D
Solution:
$ i _{g}=\frac{i}{10} $
Therefore Required shunt $ S=\frac{G}{(n-1)}=\frac{90}{(10-1)}=10,\Omega $
BETA
