Current Electricity Charging Discharging Of Capacitors Question 304

Question: The current flowing in a coil of resistance 90 W is to be reduced by 90%. What value of resistance should be connected in parallel with it

[MP PMT 2004]

Options:

A) 9 W

B) 90 W

C) 1000 W

D) 10 W

Show Answer

Answer:

Correct Answer: D

Solution:

$ i _{g}=\frac{i}{10} $

Therefore Required shunt $ S=\frac{G}{(n-1)}=\frac{90}{(10-1)}=10,\Omega $