Current Electricity Charging Discharging Of Capacitors Question 305
Question: The maximum current that can be measured by a galvanometer of resistance 40 W is 10 mA. It is converted into a voltmeter that can read upto 50 V. The resistance to be connected in series with the galvanometer is … (in ohm)
[KCET 2004]
Options:
A) 5040
B) 4960
C) 2010
D) 4050
Show Answer
Answer:
Correct Answer: B
Solution:
$ i _{g}=\frac{50}{10\times {{10}^{-3}}}-40=4960,\Omega $
BETA
