Current Electricity Charging Discharging Of Capacitors Question 307
Question: A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 ´ 10?4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of
[CBSE PMT 2004]
Options:
A) 2500 W as a shunt
B) 2450 W as a shunt
C) 2550 W in series
D) 2450 W in series
Show Answer
Answer:
Correct Answer: D
Solution:
Full deflection current $ i _{g}=25\times 4\times {{10}^{-4}} $
$ =100\times {{10}^{-4}}A $ Using $ R=\frac{V}{I _{g}}-G $
$ =\frac{25}{100\times {{10}^{-4}}}-50 $
$ =2450,\Omega $ in series.
BETA
