Current Electricity Charging Discharging Of Capacitors Question 310
Question: In given figure, the potentiometer wire AB has a resistance of 5 W and length 10 m. The balancing length AM for the emf of 0.4 V is
[Pb. PET 2001]
Options:
A) 0.4 m
B) 4 m
C) 0.8 m
D) 8 m
Show Answer
Answer:
Correct Answer: D
Solution:
$ E=\frac{e}{(R+R _{h}+r)}.\frac{R}{L}\times l $
Therefore $ 0.4=\frac{5}{(5+45+0)}\times \frac{5}{10}\times l $
Therefore l = 8 m
BETA
