Current Electricity Charging Discharging Of Capacitors Question 336
Question: $ 62.5\times 10^{18} $ electrons per second are flowing through a wire of area of cross-section 0.1 $ m^{2} $ , the value of current flowing will be
[CPMT 1984]
Options:
A) 1 A
B) 0.1 A
C) 10 A
D) 0.11 A
Show Answer
Answer:
Correct Answer: C
Solution:
$ i=\frac{ne}{t}=\frac{62.5\times 10^{18}\times 1.6\times {{10}^{-19}}}{1}=10,ampere $
BETA
