Current Electricity Charging Discharging Of Capacitors Question 344
Question: In an electrolyte $ 3.2\times 10^{18} $ bivalent positive ions drift to the right per second while $ 3.6\times 10^{18} $ monovalent negative ions drift to the left per second. Then the current is
Options:
A) 1.6 amp to the left
B) 1.6 amp to the right
C) 0.45 amp to the right
D) 0.45 amp to the left
Show Answer
Answer:
Correct Answer: B
Solution:
Net current $ i _{net}={i _{(+)}}+{i _{(-)}} $
$ =\frac{{n _{(+)}}{q _{(+)}}}{t}+\frac{{n _{(-)}}{q _{(-)}}}{t} $
$ =\frac{{n _{(+)}}}{t}\times 2e+\frac{{n _{(-)}}}{t}\times e $
$ =3.2\times 10^{18}\times 2\times 1.6\times 10^{19}+3.6\times 10^{18}\times 1.6\times 10^{19} $ = 1.6 A (towards right)
BETA
