Current Electricity Charging Discharging Of Capacitors Question 349
Question: In the above question, the resistance between the square faces is
[MP PET 1993]
Options:
A) $ 3\times {{10}^{-9}}\Omega $
B) $ 3\times {{10}^{-7}}\Omega $
C) $ 3\times {{10}^{-5}}\Omega $
D) $ 3\times {{10}^{-3}}\Omega $
Show Answer
Answer:
Correct Answer: D
Solution:
In the above question for calculating equivalent resistance between two opposite square faces. $ l=100cm=1m,A=1cm^{2}=10^{-4}m^{2} $ , so resistance $ R=3\times 10^{7}\times \frac{1}{{{10}^{-4}}}=3\times 10^{11}\Omega $
BETA
