Current Electricity Charging Discharging Of Capacitors Question 363
Question: The resistance of a wire is $ 10,\Omega $ . Its length is increased by 10% by stretching. The new resistance will now be
[CPMT 2000; Pb PET 2004]
Options:
A) $ 12,\Omega $
B) $ 1.2,\Omega $
C) $ 13,\Omega $
D) $ 11,\Omega $
Show Answer
Answer:
Correct Answer: A
Solution:
Since $ R\propto l $
Therefore, if length is increased by 10%, resistance is increased by almost 20%. Hence new resistance $ R’=10+20% $ of 10 $ =10+\frac{20}{100}\times 10=12,\Omega . $
BETA
