Current Electricity Charging Discharging Of Capacitors Question 383
Question: Two rods of same material and length have their electric resistance in ratio $ 1:2 $ . When both rods are dipped in water, the correct statement will be
[RPMT 1997]
Options:
A) A has more loss of weight
B) B has more loss of weight
C) Both have same loss of weight
D) Loss of weight will be in the ratio $ 1:2 $
Show Answer
Answer:
Correct Answer: A
Solution:
$ R=\rho \frac{l}{A}\Rightarrow \frac{R _{1}}{R _{2}}=\frac{A _{2}}{A _{1}}(\rho ,L $ constant)
$ \Rightarrow \frac{A _{1}}{A _{2}}=\frac{R _{2}}{R _{1}}=2 $ Now, when a body dipped in water, loss of weight $ =V{\sigma _{L}}g=AL{\sigma _{L}}g $ So, $ \frac{{{\text{(Loss of weight)}} _{\text{1}}}}{{{\text{(Loss of wight)}} _{\text{2}}}}=\frac{A _{1}}{A _{2}}=2; $ so A has more loss of weight.