Current Electricity Charging Discharging Of Capacitors Question 207
Question: A battery of 6 volts is connected to the terminals of a three metre long wire of uniform thickness and resistance of the order of 100 $ \Omega $ . The difference of potential between two points separated by 50 $ cm $ on the wire will be
[CPMT 1984; CBSE PMT 2004]
Options:
A) 1 V
B) 1.5 V
C) 2 V
D) 3 V
Show Answer
Answer:
Correct Answer: A
Solution:
Here same current is passing throughout the length of the wire, hence $ V\propto R\propto l $
Therefore $ \frac{V _{1}}{V _{2}}=\frac{l _{1}}{l _{2}} $
Therefore $ \frac{6}{V _{2}}=\frac{300}{50} $
Therefore V2 =1 V.
BETA
