Current Electricity Charging Discharging Of Capacitors Question 40
Question: A silver and zinc voltameter are connected in series and a current i is passed through them for a time t liberating W gm of zinc. The weight of silver deposited is nearly
[NCERT 1973, 76]
Options:
A) W
B) 1.7 W
C) 2.4 W
D) 3.5 W
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{m _{Zn}}{m _{Ag}}=\frac{E _{Zn}}{E _{Ag}} $
Therefore $ m _{Ag}=W,( \frac{E _{Ag}}{E _{Zn}} ) $ = 3.3 W = 3.5 W
BETA
