Current Electricity Charging Discharging Of Capacitors Question 424
Question: The new resistance of wire of R W, whose radius is reduced half, is
[J & K CET 2004; Pb PMT 2004]
Options:
A) 16 R
B) 3 R
C) 2R
D) R
Show Answer
Answer:
Correct Answer: A
Solution:
In stretching, $ \frac{R _{2}}{R _{1}}={{( \frac{r _{1}}{r _{2}} )}^{4}} $
$ \Rightarrow ,\frac{R _{2}}{R}={{( \frac{2}{1} )}^{4}} $
$ \Rightarrow ,R _{2}=16R $
BETA
