Current Electricity Charging Discharging Of Capacitors Question 427
Question: The electric resistance of a certain wire of iron is R. If its length and radius are both doubled, then
[CBSE PMT 2004]
Options:
A) The resistance will be doubled and the specific resistance will be halved
B) The resistance will be halved and the specific resistance will remain unchanged
C) The resistance will be halved and the specific resistance will be doubled
D) The resistance and the specific resistance, will both remain unchanged
Show Answer
Answer:
Correct Answer: B
Solution:
$ R\propto \frac{l}{r^{2}} $
Therefore $ \frac{R _{2}}{R _{1}}=\frac{l _{2}}{l _{1}}\times \frac{r _{1}^{2}}{r _{2}^{2}} $ = $ ( \frac{2}{1} )\times {{( \frac{1}{2} )}^{2}} $
$ =\frac{1}{2} $
Therefore $ R _{2}=\frac{R _{1}}{2}, $ specific resistance doesn’t depend upon length, and radius.
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