Current Electricity Charging Discharging Of Capacitors Question 101
Question: Silver and copper voltameter are connected in parallel with a battery of e.m.f. 12 V. In 30 minutes, 1 gm of silver and 1.8 gm of copper are liberated. The power supplied by the battery is
[IIT 1975]
Options:
A) 24.13 J/sec
B) 2.413 J/sec
C) 0.2413 J/sec
D) 2413 J/sec $ (Z _{Cu}=6.6\times {{10}^{-4}}gm/C $ and $ Z _{Ag}=11.2\times {{10}^{-4}},gm/C) $
Show Answer
Answer:
Correct Answer: A
Solution:
The current taken by the silver voltameter $ I _{1}=\frac{m}{Zt}=\frac{1}{11.2\times {{10}^{-4}}\times 30\times 60}=0.496A $ and by copper voltameter $ I _{2}=\frac{1.8}{6.6\times {{10}^{-4}}\times 30\times 60}=1.515A $ Total current $ I=(I _{1}+I _{2})=2.011A $ Power $ P=IV=2.011\times 12=24.132J/\sec $
BETA
