Current Electricity Charging Discharging Of Capacitors Question 462
Question: If current in an electric bulb changes by 1%, then the power will change by
[AFMC 1996]
Options:
A) 1%
B) 2%
C) 4%
D) $ \frac{1}{2}% $
Show Answer
Answer:
Correct Answer: B
Solution:
$ P=i^{2}R $
Therefore $ \frac{\Delta P}{P}=\frac{2\Delta i}{t} $ (R ® Constant)
Therefore % change in power $ =2\times $ % change in current = $ 2\times 1=2% $
BETA
