Current Electricity Charging Discharging Of Capacitors Question 472
Question: A cable of resistance $ 10,\Omega $ carries electric power from a generator producing 250 kW at 10000 volt. The current in the cable is
Options:
A) 25 A
B) 250 A
C) 100 A
D) 1000 A
Show Answer
Answer:
Correct Answer: A
Solution:
Since $ P=VI, $
Therefore $ I=\frac{P}{V}=\frac{250000}{10000}=25A $
BETA
