Current Electricity Charging Discharging Of Capacitors Question 136
Question: The resistance of a wire is $ {{10}^{-6}}\Omega $ per metre. It is bend in the form of a circle of diameter $ 2,m $ . A wire of the same material is connected across its diameter. The total resistance across its diameter AB will be
Options:
A) $ \frac{4}{3}\pi \times {{10}^{-6}}\Omega $
B) $ \frac{2}{3}\pi \times {{10}^{-6}}\Omega $
C) $ 0.88\times {{10}^{-6}}\Omega $
D) $ 14\pi \times {{10}^{-6}}\Omega $
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Answer:
Correct Answer: C
Solution:
Resistance across $ AB=\frac{1}{R’}=\frac{1}{R}+\frac{1}{R}+\frac{1}{R_{1}} $
$ R _{1}=2\times {{10}^{-6}}\Omega $ and $ R=\pi \times 1\times {{10}^{-6}}\Omega $ On solving, $ R’=0.88\times {{10}^{-6}}\Omega $
BETA
