Current Electricity Charging Discharging Of Capacitors Question 494
Question: An electric heater of resistance 6 ohm is run for 10 minutes on a 120 volt line. The energy liberated in this period of time is
[MP PMT 1996]
Options:
A) $ 7.2\times 10^{3},J $
B) $ 14.4\times 10^{5},J $
C) $ 43.2\times 10^{4},J $
D) $ 28.8\times 10^{4}J $
Show Answer
Answer:
Correct Answer: B
Solution:
$ H=i^{2}Rt=\frac{V^{2}t}{R}=\frac{120\times 120\times (10\times 60)}{6} $
$ =14.4\times 10^{5}joule $
BETA
