Current Electricity Charging Discharging Of Capacitors Question 508
Question: A current of 2 A passing through conductor produces 80 J of heat in 10 seconds. The resistance of the conductor is
[CBSE PMT 1993]
Options:
A) $ 0.5,\Omega $
B) $ 2,\Omega $
C) $ 4,\Omega $
D) $ 20,\Omega $
Show Answer
Answer:
Correct Answer: B
Solution:
$ H=i^{2}Rt $
Therefore $ R=\frac{H}{i^{2}t}=\frac{80}{4\times 10}=2\Omega $
BETA
