Current Electricity Charging Discharging Of Capacitors Question 509
Question: A $ 4\mu F $ conductor is charged to 400 volts and then its plates are joined through a resistance of $ 1,k\Omega $ . The heat produced in the resistance is
[CBSE PMT 1994]
Options:
A) 0.16 J
B) 1.28 J
C) 0.64 J
D) 0.32 J
Show Answer
Answer:
Correct Answer: D
Solution:
Heat produced = Energy stored in capacitor $ =\frac{1}{2}CV^{2} $
$ =\frac{1}{2}\times 4\times {{10}^{-6}}\times {{(400)}^{2}} $
$ =0.32J $
BETA
