Current Electricity Charging Discharging Of Capacitors Question 513
Question: A piece of fuse wire melts when a current of 15 ampere flows through it. With this current, if it dissipates 22.5 W, the resistance of fuse wire will be
[MNR 1998]
Options:
A) Zero
B) $ 10,\Omega $
C) $ 1,\Omega $
D) $ 0.10,\Omega $
Show Answer
Answer:
Correct Answer: D
Solution:
$ P=i^{2}R $
Therefore $ 22.5={{(15)}^{2}}\times R $
Therefore $ R=0.10\Omega $
BETA
