Current Electricity Charging Discharging Of Capacitors Question 518
Question: A current i passes through a wire of length l, radius of cross-section r and resistivity r. The rate of heat generation is
[AMU (Med.) 1999]
Options:
A) $ \frac{i^{2}l\rho }{\pi r^{2}} $
B) $ i^{2}{{( \frac{l\rho }{\pi r^{2}} )}^{2}} $
C) $ i^{2}l,\rho ,/,r $
D) $ i,l,\rho ,/,r $
Show Answer
Answer:
Correct Answer: A
Solution:
$ H=i^{2}Rt $
Therefore $ \frac{H}{t}=i^{2}R=\frac{i^{2}\rho l}{\pi ,r^{2}} $
BETA
