Current Electricity Charging Discharging Of Capacitors Question 52
Question: A certain charge liberates 0.8 gm of $ O _{2} $ . The same charge will liberate how many gm of silver
[MP PET 1999]
Options:
A) 108 gm
B) 10.8 gm
C) 0.8 gm
D) $ \frac{108}{0.8}gm $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{\text{Mass of }O _{2}\text{ ions}}{\text{Mass of }Ag\text{ ions}}=\frac{\text{Chemical equivalent of }O _{2}}{\text{Chemical equivalent of }Ag} $
Therefore $ \frac{0.8}{m}=\frac{8}{108} $
Therefore $ m=10.8,gm $
BETA
