Current Electricity Charging Discharging Of Capacitors Question 521
Question: On giving 220V to a resistor the power dissipated is 40W then value of resistance is
[RPMT 2000]
Options:
A) 1210 W
B) 2000 W
C) 1000 W
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ P=\frac{V^{2}}{R}\Rightarrow R=\frac{V^{2}}{P}=\frac{{{(220)}^{2}}}{40}=1210,\Omega $
BETA
