Current Electricity Charging Discharging Of Capacitors Question 525
Question: In the circuit shown below, the power developed in the 6W resistor is 6 watt. The power in watts developed in the 4W resistor is
[AMU (Med.) 2000]
Options:
A) 16
B) 9
C) 6
D) 4
Show Answer
Answer:
Correct Answer: B
Solution:
$ P=\frac{V^{2}}{R} $
Therefore $ \frac{P _{1}}{P _{2}}=\frac{R _{2}}{R _{1}} $
Therefore $ \frac{6}{P _{2}}=\frac{4}{6}=\frac{2}{3} $
Therefore $ P _{2}=9,W $
BETA
