Current Electricity Charging Discharging Of Capacitors Question 534
Question: A wire when connected to 220V mains supply has power dissipation $ P _{1} $ . Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is $ P _{2} $ . Then $ P _{2}:P _{1} $ is
[AIEEE 2002]
Options:
1
4
2
3
Show Answer
Answer:
Correct Answer: B
Solution:
When wire is cut into two equal parts then power dissipated by each part is $ \frac{P _{1}}{2} $ So their parallel combination will dissipate power $ P _{2}=\frac{P _{1}}{2}+\frac{P _{1}}{2}=P _{1} $ Which gives $ \frac{P _{2}}{P _{1}}=1 $
BETA
