Current Electricity Charging Discharging Of Capacitors Question 542
Question: A 220 volt, 1000 W bulb is connected across a 110 volt mains supply. The power consumed will be
[AIEEE 2003]
Options:
A) 1000 W
B) 750 W
C) 500 W
D) 250 W
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{P _{1}}{P _{2}}={{( \frac{V _{1}}{V _{2}} )}^{2}} $
$ \Rightarrow \frac{1000}{P _{2}}={{( \frac{220}{110} )}^{2}}=4 $
Therefore $ P _{2}=250,W $
BETA
