Current Electricity Charging Discharging Of Capacitors Question 543
Question: Two bulbs of 100 W and 200 W working at 220 volt are joined in series with 220 volt supply. Total power consumed will be approximately.
[Pb. PET 2003; BHU 2005]
Options:
A) 65 watt
B) 33 watt
C) 300 watt
D) 100 watt
Show Answer
Answer:
Correct Answer: A
Solution:
$ P _{S}=\frac{P _{1}P _{2}}{P _{1}+P _{2}}=\frac{100\times 200}{100+200}=\frac{200}{3}\approx 65,watt $
BETA
