Current Electricity Charging Discharging Of Capacitors Question 544
Question: How many calories of heat will be produced approximately in a 210 watt electric bulb in 5 minutes
[Pb. PET 2004]
Options:
A) 80000 cal
B) 63000 cal
C) 1050 cal
D) 15000 cal
Show Answer
Answer:
Correct Answer: D
Solution:
$ H=\frac{V^{2}t}{R\times J},Calories=\frac{P,t}{J}=\frac{210\times 5\times 60}{4.2}=15000,cal $
BETA
