Current Electricity Charging Discharging Of Capacitors Question 102
Question: A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silver
[EAMCET 1983]
Options:
A) Decreases by 25%
B) Increases by 25%
C) Increases by 37.5%
D) Decreases by 37.5%
Show Answer
Answer:
Correct Answer: D
Solution:
Initially current through the voltameter $ i _{1}=\frac{V}{(3+2)}=\frac{V}{5} $ Finally main current $ i=\frac{V}{3+1}=\frac{V}{4} $ Hence current through voltameter $ i _{2}=\frac{V}{8} $
$ \because $ Rate of deposition $ (R)=\frac{m}{t}=Zi $
Therefore $ R\propto i $ \ % drop in rate $ =\frac{R _{2}-R _{1}}{R _{1}}\times 100=\frac{i _{2}-i _{1}}{i _{1}}\times 100 $
$ =\frac{( \frac{V}{8}-\frac{V}{5} )}{\frac{V}{5}}\times 100=-37.5% $
BETA
