Current Electricity Charging Discharging Of Capacitors Question 551
Question: The resistor of resistance ‘R’ is connected to 25 V supply and heat produced in it is 25 J/sec. The value of R is
[Orissa PMT 2004]
Options:
A) $ 225\Omega $
B) $ 1\Omega $
C) $ 25\Omega $
D) $ 50\Omega $
Show Answer
Answer:
Correct Answer: C
Solution:
$ P=\frac{V^{2}}{R} $
Therefore $ R=\frac{V^{2}}{P}=\frac{25\times 25}{25}=25,\Omega $
BETA
