Current Electricity Charging Discharging Of Capacitors Question 570
Question: A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be
[AIEEE 2005]
Options:
A) One fourth
B) Halved
C) Doubled
D) Four times
Show Answer
Answer:
Correct Answer: C
Solution:
$ H=\frac{V^{2}t}{R} $
Therefore $ \frac{H _{Half}}{H _{Full}}=( \frac{R _{Full}}{R _{Half}} )=\frac{R}{R/2}=2 $
Therefore $ H _{Half}=2\times H _{Full} $ .
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