Current Electricity Charging Discharging Of Capacitors Question 575
Question: 3 identical bulbs are connected in series and these together dissipate a power P. If now the bulbs are connected in parallel, then the power dissipated will be
[DPMT 2005]
Options:
A) $ \frac{P}{3} $
B) 3P
C) 9P
D) $ \frac{P}{9} $
Show Answer
Answer:
Correct Answer: C
Solution:
When bulbs are connected in series, $ P=\frac{V^{2}}{{{R}’}}=\frac{V^{2}}{3R} $ When bulbs are connected in parallel, $ {P}’=\frac{V^{2}}{{{R}’’}}=\frac{V^{2}\times 3}{R}=3\times 3P=9P. $
BETA
