Current Electricity Charging Discharging Of Capacitors Question 146
Question: When connected across the terminals of a cell, a voltmeter measures 5V and a connected ammeter measures 10 A of current. A resistance of 2 ohms is connected across the terminals of the cell. The current flowing through this resistance will be
[MP PMT 1997]
Options:
A) 2.5 A
B) 2.0 A
C) 5.0 A
D) 7.5 A
Show Answer
Answer:
Correct Answer: B
Solution:
Emf E = 5V , Internal resistance $ r=\frac{5}{10}=0.5\Omega $ Current through the resistance $ i=\frac{5}{(2+0.5)}=2A $
BETA
