Current Electricity Charging Discharging Of Capacitors Question 225

Question: A voltmeter having a resistance of 998 ohms is connected to a cell of e.m.f. 2 volt and internal resistance 2 ohm. The error in the measurement of e.m.f. will be

[MP PMT 1994]

Options:

A) $ 4\times {{10}^{-1}},volt $

B) $ 2\times {{10}^{-3}}volt $

C) $ 4\times {{10}^{-3}}volt $

D) $ 2\times {{10}^{-1}}volt $

Show Answer

Answer:

Correct Answer: C

Solution:

Error in measurement = Actual value ? Measured value Actual value = 2V $ i=\frac{2}{998+2}=\frac{1}{500}A $ Since $ E=V+ir $

Therefore $ V=E-ir=2-\frac{1}{500}\times 2=\frac{998}{500}V $ \ Measured value $ =\frac{998}{500}V $

Therefore Error $ =2-\frac{998}{500}=4\times {{10}^{-3}}volt $