Current Electricity Charging Discharging Of Capacitors Question 577
Question: The battery $ E $ has an $ e.m.f. $ of $ 2,volt $ . If the galvanometer $ G $ reads zero, then the value of the resistance $ X $ in ohm is
[NCERT 1990; AIEEE 2005]
Options:
10
100
500
200
Show Answer
Answer:
Correct Answer: B
Solution:
For no current through galvanometer, we have $ ( \frac{E {1}}{500+X} )X=E{2} $
Therefore $ ( \frac{12}{500+X} )X=2 $
Therefore $ X=100\Omega $
BETA
